A taxi charges a base fee plus $0.75/km.A 10-km trip costs $8.70.a) What is the rate of change in this situation?b) Write an equation for the cost of hiring a taxi in terms of length of the trip.c) What does initial value represent in this situation.

a) The rate of change in this situation is 0.75 dollars/kmb) The equation for the cost of hiring a taxi in terms of length of thetrip is y = 0.75 x + bc) The initial value represents in this situation is $1.2Step-by-step explanation:The given is:A taxi charges a base fee plus $0.75/km.A 10-km trip costs $8.70∵ A rate of change is a rate that describes how one quantity   changes in relation to another quantity∵ The unit cost of a taxi is 0.75 dollars for each 1 kilometer∴ The rate of change = 0.75 dollars/kma) The rate of change in this situation is 0.75 dollars/kmAssume that the cost of hiring a taxi is $y for length of a trip x kmand a base fee of $b∵ The length of the trip = x km∵ The cost per km = $0.75∵ The base fee = $b∵ The cost of hiring a taxi = $y- Write an equation for the the cost of hiring a taxi∴ y = 0.75 x + bb) The equation for the cost of hiring a taxi in terms of length of the trip is y = 0.75 x + b∵ The length of the trip is 10 km∴ x = 10∵ The cost of the hiring a taxi is $8.70 ∴ y = 8.70- Substitute these values in the equation of part (b)∵ y = 0.75 x + b∴ 8.70 = 0.75(10) + b∴ 8.70 = 7.5 + b- Subtract 7.5 from both sides∴ 1.2 = b∵ b is the base fee∴ b is the initial value∴ The initial value = $1.2c) The initial value represents in this situation is $1.2Learn more:You can learn more about word problems in brainly.com/question/3950386#LearnwithBrainly